3.5.40 \(\int \frac {1}{x^3 (8 c-d x^3)^2 \sqrt {c+d x^3}} \, dx\) [440]

Optimal. Leaf size=66 \[ -\frac {\sqrt {1+\frac {d x^3}{c}} F_1\left (-\frac {2}{3};2,\frac {1}{2};\frac {1}{3};\frac {d x^3}{8 c},-\frac {d x^3}{c}\right )}{128 c^2 x^2 \sqrt {c+d x^3}} \]

[Out]

-1/128*AppellF1(-2/3,1/2,2,1/3,-d*x^3/c,1/8*d*x^3/c)*(1+d*x^3/c)^(1/2)/c^2/x^2/(d*x^3+c)^(1/2)

________________________________________________________________________________________

Rubi [A]
time = 0.04, antiderivative size = 66, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 27, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.074, Rules used = {525, 524} \begin {gather*} -\frac {\sqrt {\frac {d x^3}{c}+1} F_1\left (-\frac {2}{3};2,\frac {1}{2};\frac {1}{3};\frac {d x^3}{8 c},-\frac {d x^3}{c}\right )}{128 c^2 x^2 \sqrt {c+d x^3}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[1/(x^3*(8*c - d*x^3)^2*Sqrt[c + d*x^3]),x]

[Out]

-1/128*(Sqrt[1 + (d*x^3)/c]*AppellF1[-2/3, 2, 1/2, 1/3, (d*x^3)/(8*c), -((d*x^3)/c)])/(c^2*x^2*Sqrt[c + d*x^3]
)

Rule 524

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^(q_), x_Symbol] :> Simp[a^p*c^q*
((e*x)^(m + 1)/(e*(m + 1)))*AppellF1[(m + 1)/n, -p, -q, 1 + (m + 1)/n, (-b)*(x^n/a), (-d)*(x^n/c)], x] /; Free
Q[{a, b, c, d, e, m, n, p, q}, x] && NeQ[b*c - a*d, 0] && NeQ[m, -1] && NeQ[m, n - 1] && (IntegerQ[p] || GtQ[a
, 0]) && (IntegerQ[q] || GtQ[c, 0])

Rule 525

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^(q_), x_Symbol] :> Dist[a^IntPar
t[p]*((a + b*x^n)^FracPart[p]/(1 + b*(x^n/a))^FracPart[p]), Int[(e*x)^m*(1 + b*(x^n/a))^p*(c + d*x^n)^q, x], x
] /; FreeQ[{a, b, c, d, e, m, n, p, q}, x] && NeQ[b*c - a*d, 0] && NeQ[m, -1] && NeQ[m, n - 1] &&  !(IntegerQ[
p] || GtQ[a, 0])

Rubi steps

\begin {align*} \int \frac {1}{x^3 \left (8 c-d x^3\right )^2 \sqrt {c+d x^3}} \, dx &=\frac {\sqrt {1+\frac {d x^3}{c}} \int \frac {1}{x^3 \left (8 c-d x^3\right )^2 \sqrt {1+\frac {d x^3}{c}}} \, dx}{\sqrt {c+d x^3}}\\ &=-\frac {\sqrt {1+\frac {d x^3}{c}} F_1\left (-\frac {2}{3};2,\frac {1}{2};\frac {1}{3};\frac {d x^3}{8 c},-\frac {d x^3}{c}\right )}{128 c^2 x^2 \sqrt {c+d x^3}}\\ \end {align*}

________________________________________________________________________________________

Mathematica [B] Leaf count is larger than twice the leaf count of optimal. \(266\) vs. \(2(66)=132\).
time = 10.12, size = 266, normalized size = 4.03 \begin {gather*} \frac {-\frac {64 \left (c+d x^3\right ) \left (-216 c+29 d x^3\right )}{c^3 x^2 \left (-8 c+d x^3\right )}+\frac {29 d^2 x^4 \sqrt {1+\frac {d x^3}{c}} F_1\left (\frac {4}{3};\frac {1}{2},1;\frac {7}{3};-\frac {d x^3}{c},\frac {d x^3}{8 c}\right )}{c^4}-\frac {4096 d x F_1\left (\frac {1}{3};\frac {1}{2},1;\frac {4}{3};-\frac {d x^3}{c},\frac {d x^3}{8 c}\right )}{c \left (8 c-d x^3\right ) \left (32 c F_1\left (\frac {1}{3};\frac {1}{2},1;\frac {4}{3};-\frac {d x^3}{c},\frac {d x^3}{8 c}\right )+3 d x^3 \left (F_1\left (\frac {4}{3};\frac {1}{2},2;\frac {7}{3};-\frac {d x^3}{c},\frac {d x^3}{8 c}\right )-4 F_1\left (\frac {4}{3};\frac {3}{2},1;\frac {7}{3};-\frac {d x^3}{c},\frac {d x^3}{8 c}\right )\right )\right )}}{221184 \sqrt {c+d x^3}} \end {gather*}

Warning: Unable to verify antiderivative.

[In]

Integrate[1/(x^3*(8*c - d*x^3)^2*Sqrt[c + d*x^3]),x]

[Out]

((-64*(c + d*x^3)*(-216*c + 29*d*x^3))/(c^3*x^2*(-8*c + d*x^3)) + (29*d^2*x^4*Sqrt[1 + (d*x^3)/c]*AppellF1[4/3
, 1/2, 1, 7/3, -((d*x^3)/c), (d*x^3)/(8*c)])/c^4 - (4096*d*x*AppellF1[1/3, 1/2, 1, 4/3, -((d*x^3)/c), (d*x^3)/
(8*c)])/(c*(8*c - d*x^3)*(32*c*AppellF1[1/3, 1/2, 1, 4/3, -((d*x^3)/c), (d*x^3)/(8*c)] + 3*d*x^3*(AppellF1[4/3
, 1/2, 2, 7/3, -((d*x^3)/c), (d*x^3)/(8*c)] - 4*AppellF1[4/3, 3/2, 1, 7/3, -((d*x^3)/c), (d*x^3)/(8*c)]))))/(2
21184*Sqrt[c + d*x^3])

________________________________________________________________________________________

Maple [C] Result contains higher order function than in optimal. Order 9 vs. order 6.
time = 0.45, size = 1456, normalized size = 22.06

method result size
elliptic \(-\frac {\sqrt {d \,x^{3}+c}}{128 c^{3} x^{2}}+\frac {d x \sqrt {d \,x^{3}+c}}{1728 c^{3} \left (-d \,x^{3}+8 c \right )}+\frac {29 i \sqrt {3}\, \left (-c \,d^{2}\right )^{\frac {1}{3}} \sqrt {\frac {i \left (x +\frac {\left (-c \,d^{2}\right )^{\frac {1}{3}}}{2 d}-\frac {i \sqrt {3}\, \left (-c \,d^{2}\right )^{\frac {1}{3}}}{2 d}\right ) \sqrt {3}\, d}{\left (-c \,d^{2}\right )^{\frac {1}{3}}}}\, \sqrt {\frac {x -\frac {\left (-c \,d^{2}\right )^{\frac {1}{3}}}{d}}{-\frac {3 \left (-c \,d^{2}\right )^{\frac {1}{3}}}{2 d}+\frac {i \sqrt {3}\, \left (-c \,d^{2}\right )^{\frac {1}{3}}}{2 d}}}\, \sqrt {-\frac {i \left (x +\frac {\left (-c \,d^{2}\right )^{\frac {1}{3}}}{2 d}+\frac {i \sqrt {3}\, \left (-c \,d^{2}\right )^{\frac {1}{3}}}{2 d}\right ) \sqrt {3}\, d}{\left (-c \,d^{2}\right )^{\frac {1}{3}}}}\, \EllipticF \left (\frac {\sqrt {3}\, \sqrt {\frac {i \left (x +\frac {\left (-c \,d^{2}\right )^{\frac {1}{3}}}{2 d}-\frac {i \sqrt {3}\, \left (-c \,d^{2}\right )^{\frac {1}{3}}}{2 d}\right ) \sqrt {3}\, d}{\left (-c \,d^{2}\right )^{\frac {1}{3}}}}}{3}, \sqrt {\frac {i \sqrt {3}\, \left (-c \,d^{2}\right )^{\frac {1}{3}}}{d \left (-\frac {3 \left (-c \,d^{2}\right )^{\frac {1}{3}}}{2 d}+\frac {i \sqrt {3}\, \left (-c \,d^{2}\right )^{\frac {1}{3}}}{2 d}\right )}}\right )}{10368 c^{3} \sqrt {d \,x^{3}+c}}-\frac {19 i \sqrt {2}\, \left (\munderset {\underline {\hspace {1.25 ex}}\alpha =\RootOf \left (d \,\textit {\_Z}^{3}-8 c \right )}{\sum }\frac {\left (-c \,d^{2}\right )^{\frac {1}{3}} \sqrt {2}\, \sqrt {\frac {i d \left (2 x +\frac {-i \sqrt {3}\, \left (-c \,d^{2}\right )^{\frac {1}{3}}+\left (-c \,d^{2}\right )^{\frac {1}{3}}}{d}\right )}{\left (-c \,d^{2}\right )^{\frac {1}{3}}}}\, \sqrt {\frac {d \left (x -\frac {\left (-c \,d^{2}\right )^{\frac {1}{3}}}{d}\right )}{-3 \left (-c \,d^{2}\right )^{\frac {1}{3}}+i \sqrt {3}\, \left (-c \,d^{2}\right )^{\frac {1}{3}}}}\, \sqrt {-\frac {i d \left (2 x +\frac {i \sqrt {3}\, \left (-c \,d^{2}\right )^{\frac {1}{3}}+\left (-c \,d^{2}\right )^{\frac {1}{3}}}{d}\right )}{2 \left (-c \,d^{2}\right )^{\frac {1}{3}}}}\, \left (i \left (-c \,d^{2}\right )^{\frac {1}{3}} \underline {\hspace {1.25 ex}}\alpha \sqrt {3}\, d -i \sqrt {3}\, \left (-c \,d^{2}\right )^{\frac {2}{3}}+2 \underline {\hspace {1.25 ex}}\alpha ^{2} d^{2}-\left (-c \,d^{2}\right )^{\frac {1}{3}} \underline {\hspace {1.25 ex}}\alpha d -\left (-c \,d^{2}\right )^{\frac {2}{3}}\right ) \EllipticPi \left (\frac {\sqrt {3}\, \sqrt {\frac {i \left (x +\frac {\left (-c \,d^{2}\right )^{\frac {1}{3}}}{2 d}-\frac {i \sqrt {3}\, \left (-c \,d^{2}\right )^{\frac {1}{3}}}{2 d}\right ) \sqrt {3}\, d}{\left (-c \,d^{2}\right )^{\frac {1}{3}}}}}{3}, -\frac {2 i \left (-c \,d^{2}\right )^{\frac {1}{3}} \sqrt {3}\, \underline {\hspace {1.25 ex}}\alpha ^{2} d -i \left (-c \,d^{2}\right )^{\frac {2}{3}} \sqrt {3}\, \underline {\hspace {1.25 ex}}\alpha +i \sqrt {3}\, c d -3 \left (-c \,d^{2}\right )^{\frac {2}{3}} \underline {\hspace {1.25 ex}}\alpha -3 c d}{18 d c}, \sqrt {\frac {i \sqrt {3}\, \left (-c \,d^{2}\right )^{\frac {1}{3}}}{d \left (-\frac {3 \left (-c \,d^{2}\right )^{\frac {1}{3}}}{2 d}+\frac {i \sqrt {3}\, \left (-c \,d^{2}\right )^{\frac {1}{3}}}{2 d}\right )}}\right )}{2 \underline {\hspace {1.25 ex}}\alpha ^{2} \sqrt {d \,x^{3}+c}}\right )}{15552 c^{3} d^{2}}\) \(744\)
default \(\text {Expression too large to display}\) \(1456\)
risch \(\text {Expression too large to display}\) \(1457\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/x^3/(-d*x^3+8*c)^2/(d*x^3+c)^(1/2),x,method=_RETURNVERBOSE)

[Out]

1/64/c^2*(-1/2/c*(d*x^3+c)^(1/2)/x^2+1/6*I/c*3^(1/2)*(-c*d^2)^(1/3)*(I*(x+1/2/d*(-c*d^2)^(1/3)-1/2*I*3^(1/2)/d
*(-c*d^2)^(1/3))*3^(1/2)*d/(-c*d^2)^(1/3))^(1/2)*((x-1/d*(-c*d^2)^(1/3))/(-3/2/d*(-c*d^2)^(1/3)+1/2*I*3^(1/2)/
d*(-c*d^2)^(1/3)))^(1/2)*(-I*(x+1/2/d*(-c*d^2)^(1/3)+1/2*I*3^(1/2)/d*(-c*d^2)^(1/3))*3^(1/2)*d/(-c*d^2)^(1/3))
^(1/2)/(d*x^3+c)^(1/2)*EllipticF(1/3*3^(1/2)*(I*(x+1/2/d*(-c*d^2)^(1/3)-1/2*I*3^(1/2)/d*(-c*d^2)^(1/3))*3^(1/2
)*d/(-c*d^2)^(1/3))^(1/2),(I*3^(1/2)/d*(-c*d^2)^(1/3)/(-3/2/d*(-c*d^2)^(1/3)+1/2*I*3^(1/2)/d*(-c*d^2)^(1/3)))^
(1/2)))-1/1728*I/d^2/c^3*2^(1/2)*sum(1/_alpha^2*(-c*d^2)^(1/3)*(1/2*I*d*(2*x+1/d*(-I*3^(1/2)*(-c*d^2)^(1/3)+(-
c*d^2)^(1/3)))/(-c*d^2)^(1/3))^(1/2)*(d*(x-1/d*(-c*d^2)^(1/3))/(-3*(-c*d^2)^(1/3)+I*3^(1/2)*(-c*d^2)^(1/3)))^(
1/2)*(-1/2*I*d*(2*x+1/d*(I*3^(1/2)*(-c*d^2)^(1/3)+(-c*d^2)^(1/3)))/(-c*d^2)^(1/3))^(1/2)/(d*x^3+c)^(1/2)*(I*(-
c*d^2)^(1/3)*_alpha*3^(1/2)*d-I*3^(1/2)*(-c*d^2)^(2/3)+2*_alpha^2*d^2-(-c*d^2)^(1/3)*_alpha*d-(-c*d^2)^(2/3))*
EllipticPi(1/3*3^(1/2)*(I*(x+1/2/d*(-c*d^2)^(1/3)-1/2*I*3^(1/2)/d*(-c*d^2)^(1/3))*3^(1/2)*d/(-c*d^2)^(1/3))^(1
/2),-1/18/d*(2*I*(-c*d^2)^(1/3)*3^(1/2)*_alpha^2*d-I*(-c*d^2)^(2/3)*3^(1/2)*_alpha+I*3^(1/2)*c*d-3*(-c*d^2)^(2
/3)*_alpha-3*c*d)/c,(I*3^(1/2)/d*(-c*d^2)^(1/3)/(-3/2/d*(-c*d^2)^(1/3)+1/2*I*3^(1/2)/d*(-c*d^2)^(1/3)))^(1/2))
,_alpha=RootOf(_Z^3*d-8*c))+1/8*d/c*(1/216*x/c^2*(d*x^3+c)^(1/2)/(-d*x^3+8*c)+1/648*I/c^2*3^(1/2)/d*(-c*d^2)^(
1/3)*(I*(x+1/2/d*(-c*d^2)^(1/3)-1/2*I*3^(1/2)/d*(-c*d^2)^(1/3))*3^(1/2)*d/(-c*d^2)^(1/3))^(1/2)*((x-1/d*(-c*d^
2)^(1/3))/(-3/2/d*(-c*d^2)^(1/3)+1/2*I*3^(1/2)/d*(-c*d^2)^(1/3)))^(1/2)*(-I*(x+1/2/d*(-c*d^2)^(1/3)+1/2*I*3^(1
/2)/d*(-c*d^2)^(1/3))*3^(1/2)*d/(-c*d^2)^(1/3))^(1/2)/(d*x^3+c)^(1/2)*EllipticF(1/3*3^(1/2)*(I*(x+1/2/d*(-c*d^
2)^(1/3)-1/2*I*3^(1/2)/d*(-c*d^2)^(1/3))*3^(1/2)*d/(-c*d^2)^(1/3))^(1/2),(I*3^(1/2)/d*(-c*d^2)^(1/3)/(-3/2/d*(
-c*d^2)^(1/3)+1/2*I*3^(1/2)/d*(-c*d^2)^(1/3)))^(1/2))-5/972*I/c^2/d^3*2^(1/2)*sum(1/_alpha^2*(-c*d^2)^(1/3)*(1
/2*I*d*(2*x+1/d*(-I*3^(1/2)*(-c*d^2)^(1/3)+(-c*d^2)^(1/3)))/(-c*d^2)^(1/3))^(1/2)*(d*(x-1/d*(-c*d^2)^(1/3))/(-
3*(-c*d^2)^(1/3)+I*3^(1/2)*(-c*d^2)^(1/3)))^(1/2)*(-1/2*I*d*(2*x+1/d*(I*3^(1/2)*(-c*d^2)^(1/3)+(-c*d^2)^(1/3))
)/(-c*d^2)^(1/3))^(1/2)/(d*x^3+c)^(1/2)*(I*(-c*d^2)^(1/3)*_alpha*3^(1/2)*d-I*3^(1/2)*(-c*d^2)^(2/3)+2*_alpha^2
*d^2-(-c*d^2)^(1/3)*_alpha*d-(-c*d^2)^(2/3))*EllipticPi(1/3*3^(1/2)*(I*(x+1/2/d*(-c*d^2)^(1/3)-1/2*I*3^(1/2)/d
*(-c*d^2)^(1/3))*3^(1/2)*d/(-c*d^2)^(1/3))^(1/2),-1/18/d*(2*I*(-c*d^2)^(1/3)*3^(1/2)*_alpha^2*d-I*(-c*d^2)^(2/
3)*3^(1/2)*_alpha+I*3^(1/2)*c*d-3*(-c*d^2)^(2/3)*_alpha-3*c*d)/c,(I*3^(1/2)/d*(-c*d^2)^(1/3)/(-3/2/d*(-c*d^2)^
(1/3)+1/2*I*3^(1/2)/d*(-c*d^2)^(1/3)))^(1/2)),_alpha=RootOf(_Z^3*d-8*c)))

________________________________________________________________________________________

Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^3/(-d*x^3+8*c)^2/(d*x^3+c)^(1/2),x, algorithm="maxima")

[Out]

integrate(1/(sqrt(d*x^3 + c)*(d*x^3 - 8*c)^2*x^3), x)

________________________________________________________________________________________

Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 2677 vs. \(2 (52) = 104\).
time = 11.24, size = 2677, normalized size = 40.56 \begin {gather*} \text {Too large to display} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^3/(-d*x^3+8*c)^2/(d*x^3+c)^(1/2),x, algorithm="fricas")

[Out]

1/248832*(76*sqrt(3)*(c^3*d*x^5 - 8*c^4*x^2)*(d^4/c^19)^(1/6)*arctan(1/9*((9*sqrt(3)*c^16*d^4*x^5*(d^4/c^19)^(
5/6) + 3*sqrt(3)*(5*c^10*d^5*x^4 + 8*c^11*d^4*x)*sqrt(d^4/c^19) - sqrt(3)*(c^3*d^7*x^6 - 40*c^4*d^6*x^3 - 32*c
^5*d^5)*(d^4/c^19)^(1/6))*sqrt(d*x^3 + c) - (12*sqrt(3)*(c^13*d^2*x^6 - c^14*d*x^3 - 2*c^15)*(d^4/c^19)^(2/3)
+ 18*sqrt(3)*(c^7*d^3*x^5 + c^8*d^2*x^2)*(d^4/c^19)^(1/3) + 3*sqrt(3)*(d^5*x^7 + 5*c*d^4*x^4 + 4*c^2*d^3*x) -
sqrt(d*x^3 + c)*(9*sqrt(3)*(c^16*d*x^5 + 2*c^17*x^2)*(d^4/c^19)^(5/6) + 3*sqrt(3)*(7*c^10*d^2*x^4 + 4*c^11*d*x
)*sqrt(d^4/c^19) + sqrt(3)*(c^3*d^4*x^6 + 32*c^4*d^3*x^3 + 40*c^5*d^2)*(d^4/c^19)^(1/6)))*sqrt((d^9*x^9 - 276*
c*d^8*x^6 - 1608*c^2*d^7*x^3 - 1088*c^3*d^6 + 18*(c^13*d^6*x^8 + 20*c^14*d^5*x^5 - 8*c^15*d^4*x^2)*(d^4/c^19)^
(2/3) + 6*sqrt(d*x^3 + c)*((c^16*d^5*x^7 - 28*c^17*d^4*x^4 - 272*c^18*d^3*x)*(d^4/c^19)^(5/6) + 4*(c^10*d^6*x^
6 + 41*c^11*d^5*x^3 + 40*c^12*d^4)*sqrt(d^4/c^19) - 24*(c^4*d^7*x^5 + c^5*d^6*x^2)*(d^4/c^19)^(1/6)) - 18*(c^7
*d^7*x^7 - 52*c^8*d^6*x^4 - 80*c^9*d^5*x)*(d^4/c^19)^(1/3))/(d^3*x^9 - 24*c*d^2*x^6 + 192*c^2*d*x^3 - 512*c^3)
))/(d^8*x^7 - 7*c*d^7*x^4 - 8*c^2*d^6*x)) + 76*sqrt(3)*(c^3*d*x^5 - 8*c^4*x^2)*(d^4/c^19)^(1/6)*arctan(1/9*((9
*sqrt(3)*c^16*d^4*x^5*(d^4/c^19)^(5/6) + 3*sqrt(3)*(5*c^10*d^5*x^4 + 8*c^11*d^4*x)*sqrt(d^4/c^19) - sqrt(3)*(c
^3*d^7*x^6 - 40*c^4*d^6*x^3 - 32*c^5*d^5)*(d^4/c^19)^(1/6))*sqrt(d*x^3 + c) + (12*sqrt(3)*(c^13*d^2*x^6 - c^14
*d*x^3 - 2*c^15)*(d^4/c^19)^(2/3) + 18*sqrt(3)*(c^7*d^3*x^5 + c^8*d^2*x^2)*(d^4/c^19)^(1/3) + 3*sqrt(3)*(d^5*x
^7 + 5*c*d^4*x^4 + 4*c^2*d^3*x) + sqrt(d*x^3 + c)*(9*sqrt(3)*(c^16*d*x^5 + 2*c^17*x^2)*(d^4/c^19)^(5/6) + 3*sq
rt(3)*(7*c^10*d^2*x^4 + 4*c^11*d*x)*sqrt(d^4/c^19) + sqrt(3)*(c^3*d^4*x^6 + 32*c^4*d^3*x^3 + 40*c^5*d^2)*(d^4/
c^19)^(1/6)))*sqrt((d^9*x^9 - 276*c*d^8*x^6 - 1608*c^2*d^7*x^3 - 1088*c^3*d^6 + 18*(c^13*d^6*x^8 + 20*c^14*d^5
*x^5 - 8*c^15*d^4*x^2)*(d^4/c^19)^(2/3) - 6*sqrt(d*x^3 + c)*((c^16*d^5*x^7 - 28*c^17*d^4*x^4 - 272*c^18*d^3*x)
*(d^4/c^19)^(5/6) + 4*(c^10*d^6*x^6 + 41*c^11*d^5*x^3 + 40*c^12*d^4)*sqrt(d^4/c^19) - 24*(c^4*d^7*x^5 + c^5*d^
6*x^2)*(d^4/c^19)^(1/6)) - 18*(c^7*d^7*x^7 - 52*c^8*d^6*x^4 - 80*c^9*d^5*x)*(d^4/c^19)^(1/3))/(d^3*x^9 - 24*c*
d^2*x^6 + 192*c^2*d*x^3 - 512*c^3)))/(d^8*x^7 - 7*c*d^7*x^4 - 8*c^2*d^6*x)) - 720*(d*x^5 - 8*c*x^2)*sqrt(d)*we
ierstrassPInverse(0, -4*c/d, x) + 19*(c^3*d*x^5 - 8*c^4*x^2)*(d^4/c^19)^(1/6)*log(6131066257801*(d^9*x^9 - 276
*c*d^8*x^6 - 1608*c^2*d^7*x^3 - 1088*c^3*d^6 + 18*(c^13*d^6*x^8 + 20*c^14*d^5*x^5 - 8*c^15*d^4*x^2)*(d^4/c^19)
^(2/3) + 6*sqrt(d*x^3 + c)*((c^16*d^5*x^7 - 28*c^17*d^4*x^4 - 272*c^18*d^3*x)*(d^4/c^19)^(5/6) + 4*(c^10*d^6*x
^6 + 41*c^11*d^5*x^3 + 40*c^12*d^4)*sqrt(d^4/c^19) - 24*(c^4*d^7*x^5 + c^5*d^6*x^2)*(d^4/c^19)^(1/6)) - 18*(c^
7*d^7*x^7 - 52*c^8*d^6*x^4 - 80*c^9*d^5*x)*(d^4/c^19)^(1/3))/(d^3*x^9 - 24*c*d^2*x^6 + 192*c^2*d*x^3 - 512*c^3
)) - 19*(c^3*d*x^5 - 8*c^4*x^2)*(d^4/c^19)^(1/6)*log(6131066257801*(d^9*x^9 - 276*c*d^8*x^6 - 1608*c^2*d^7*x^3
 - 1088*c^3*d^6 + 18*(c^13*d^6*x^8 + 20*c^14*d^5*x^5 - 8*c^15*d^4*x^2)*(d^4/c^19)^(2/3) - 6*sqrt(d*x^3 + c)*((
c^16*d^5*x^7 - 28*c^17*d^4*x^4 - 272*c^18*d^3*x)*(d^4/c^19)^(5/6) + 4*(c^10*d^6*x^6 + 41*c^11*d^5*x^3 + 40*c^1
2*d^4)*sqrt(d^4/c^19) - 24*(c^4*d^7*x^5 + c^5*d^6*x^2)*(d^4/c^19)^(1/6)) - 18*(c^7*d^7*x^7 - 52*c^8*d^6*x^4 -
80*c^9*d^5*x)*(d^4/c^19)^(1/3))/(d^3*x^9 - 24*c*d^2*x^6 + 192*c^2*d*x^3 - 512*c^3)) + 38*(c^3*d*x^5 - 8*c^4*x^
2)*(d^4/c^19)^(1/6)*log(2476099*(d^6*x^9 + 318*c*d^5*x^6 + 1200*c^2*d^4*x^3 + 640*c^3*d^3 + 18*(c^13*d^3*x^8 +
 38*c^14*d^2*x^5 + 64*c^15*d*x^2)*(d^4/c^19)^(2/3) + 6*sqrt(d*x^3 + c)*((c^16*d^2*x^7 + 80*c^17*d*x^4 + 160*c^
18*x)*(d^4/c^19)^(5/6) + (7*c^10*d^3*x^6 + 152*c^11*d^2*x^3 + 64*c^12*d)*sqrt(d^4/c^19) + 6*(5*c^4*d^4*x^5 + 3
2*c^5*d^3*x^2)*(d^4/c^19)^(1/6)) + 18*(5*c^7*d^4*x^7 + 64*c^8*d^3*x^4 + 32*c^9*d^2*x)*(d^4/c^19)^(1/3))/(d^3*x
^9 - 24*c*d^2*x^6 + 192*c^2*d*x^3 - 512*c^3)) - 38*(c^3*d*x^5 - 8*c^4*x^2)*(d^4/c^19)^(1/6)*log(2476099*(d^6*x
^9 + 318*c*d^5*x^6 + 1200*c^2*d^4*x^3 + 640*c^3*d^3 + 18*(c^13*d^3*x^8 + 38*c^14*d^2*x^5 + 64*c^15*d*x^2)*(d^4
/c^19)^(2/3) - 6*sqrt(d*x^3 + c)*((c^16*d^2*x^7 + 80*c^17*d*x^4 + 160*c^18*x)*(d^4/c^19)^(5/6) + (7*c^10*d^3*x
^6 + 152*c^11*d^2*x^3 + 64*c^12*d)*sqrt(d^4/c^19) + 6*(5*c^4*d^4*x^5 + 32*c^5*d^3*x^2)*(d^4/c^19)^(1/6)) + 18*
(5*c^7*d^4*x^7 + 64*c^8*d^3*x^4 + 32*c^9*d^2*x)*(d^4/c^19)^(1/3))/(d^3*x^9 - 24*c*d^2*x^6 + 192*c^2*d*x^3 - 51
2*c^3)) - 72*(29*d*x^3 - 216*c)*sqrt(d*x^3 + c))/(c^3*d*x^5 - 8*c^4*x^2)

________________________________________________________________________________________

Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{x^{3} \left (- 8 c + d x^{3}\right )^{2} \sqrt {c + d x^{3}}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x**3/(-d*x**3+8*c)**2/(d*x**3+c)**(1/2),x)

[Out]

Integral(1/(x**3*(-8*c + d*x**3)**2*sqrt(c + d*x**3)), x)

________________________________________________________________________________________

Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^3/(-d*x^3+8*c)^2/(d*x^3+c)^(1/2),x, algorithm="giac")

[Out]

integrate(1/(sqrt(d*x^3 + c)*(d*x^3 - 8*c)^2*x^3), x)

________________________________________________________________________________________

Mupad [F]
time = 0.00, size = -1, normalized size = -0.02 \begin {gather*} \int \frac {1}{x^3\,\sqrt {d\,x^3+c}\,{\left (8\,c-d\,x^3\right )}^2} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x^3*(c + d*x^3)^(1/2)*(8*c - d*x^3)^2),x)

[Out]

int(1/(x^3*(c + d*x^3)^(1/2)*(8*c - d*x^3)^2), x)

________________________________________________________________________________________